Step 1 :
Equation at the end of step 1 :
v (v2) 9 ((2u+(2•—))+v)+((3•((((4•(u2))+(4•————))+v)-3))•(((((u2)+2uv)+(v2))-(——•(u4)))-24v4)) u u 16Step 2 :
9 Simplify —— 16
Equation at the end of step 2 :
v (v2) 9 ((2u+(2•—))+v)+((3•((((4•(u2))+(4•————))+v)-3))•(((((u2)+2uv)+(v2))-(——•u4))-24v4)) u u 16
Step 3 :
Equation at the end of step 3 :
v (v2) 9u4 ((2u+(2•—))+v)+((3•((((4•(u2))+(4•————))+v)-3))•(((((u2)+2uv)+(v2))-———)-24v4)) u u 16
Step 4 :
Rewriting the whole as an Equivalent Fraction :
4.1Subtracting a fraction from a whole
Rewrite the whole as a fraction using 16 as the denominator :
u2 + 2uv + v2 (u2 + 2uv + v2) • 16 u2 + 2uv + v2 = ————————————— = ———————————————————— 1 16
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Trying to factor a multi variable polynomial :
4.2 Factoringu2 + 2uv + v2
Try to factor this multi-variable trinomial using trial and errorFound a factorization:(u + v)•(u + v)
Detecting a perfect square :
4.3u2+2uv+v2 is a perfect squareIt factors into (u+v)•(u+v)
which is another way of writing (u+v)2
How to recognize a perfect square trinomial: • It has three terms • Two of its terms are perfect squares themselves • The remaining term is twice the product of the square roots of the other two terms
Adding fractions that have a common denominator :
4.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
(u+v)2 • 16 - (9u4) -9u4 + 16u2 + 32uv + 16v2 ——————————————————— = ————————————————————————— 16 16
Equation at the end of step 4 :
v (v2) (-9u4+16u2+32uv+16v2) ((2u+(2•—))+v)+((3•((((4•(u2))+(4•————))+v)-3))•(—————————————————————-24v4)) u u 16
Step 5 :
Rewriting the whole as an Equivalent Fraction :
5.1Subtracting a whole from a fraction
Rewrite the whole as a fraction using 16 as the denominator :
24v4 24v4 • 16 24v4 = ———— = ————————— 1 16
Checking for a perfect cube :
5.2-9u4 + 16u2 + 32uv + 16v2 is not a perfect cube
Adding fractions that have a common denominator :
5.3 Adding up the two equivalent fractions
(-9u4+16u2+32uv+16v2) - (24v4 • 16) -9u4 + 16u2 + 32uv - 256v4 + 16v2 ——————————————————————————————————— = ————————————————————————————————— 16 16
Equation at the end of step 5 :
v (v2) (-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+((3•((((4•(u2))+(4•————))+v)-3))•———————————————————————————) u u 16Step 6 :
v2 Simplify —— u
Equation at the end of step 6 :
v v2 (-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+((3•((((4•(u2))+(4•——))+v)-3))•———————————————————————————) u u 16Step 7 :
Equation at the end of step 7 :
v 4v2 (-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+((3•(((22u2+———)+v)-3))•———————————————————————————) u u 16
Step 8 :
Rewriting the whole as an Equivalent Fraction :
8.1Adding a fraction to a whole
Rewrite the whole as a fraction using u as the denominator :
22u2 22u2 • u 22u2 = ———— = ———————— 1 u
Adding fractions that have a common denominator :
8.2 Adding up the two equivalent fractions
22u2 • u + 4v2 4u3 + 4v2 —————————————— = ————————— u u
Equation at the end of step 8 :
v (4u3+4v2) (-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+((3•((—————————+v)-3))•———————————————————————————) u u 16
Step 9 :
Rewriting the whole as an Equivalent Fraction :
9.1Adding a whole to a fraction
Rewrite the whole as a fraction using u as the denominator :
v v • u v = — = ————— 1 u
Step 10 :
Pulling out like terms :
10.1 Pull out like factors:
4u3 + 4v2=4•(u3 + v2)
Trying to factor as a Sum of Cubes:
10.2 Factoring: u3 + v2
Theory:A sum of two perfect cubes, a3+b3 can be factored into :
(a+b)•(a2-ab+b2)
Proof: (a+b)•(a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3=
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
Check: u3 is the cube of u1
Check: v 2 is not a cube !!
Ruling:Binomial can not be factored as the difference of two perfect cubes
Adding fractions that have a common denominator :
10.3 Adding up the two equivalent fractions
4 • (u3+v2) + v • u 4u3 + uv + 4v2 ——————————————————— = —————————————— u u
Equation at the end of step 10 :
v (4u3+uv+4v2) (-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+((3•(————————————-3))•———————————————————————————) u u 16
Step 11 :
Rewriting the whole as an Equivalent Fraction :
11.1Subtracting a whole from a fraction
Rewrite the whole as a fraction using u as the denominator :
3 3 • u 3 = — = ————— 1 u
Trying to factor a multi variable polynomial :
11.2 Factoring4u3 + uv + 4v2
Try to factor this multi-variable trinomial using trial and errorFactorization fails
Adding fractions that have a common denominator :
11.3 Adding up the two equivalent fractions
(4u3+uv+4v2) - (3 • u) 4u3 + uv - 3u + 4v2 —————————————————————— = ——————————————————— u u
Equation at the end of step 11 :
v (4u3+uv-3u+4v2) (-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+((3•———————————————)•———————————————————————————) u u 16
Step 12 :
Checking for a perfect cube :
12.14u3+uv-3u+4v2 is not a perfect cube
Equation at the end of step 12 :
v 3•(4u3+uv-3u+4v2) (-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+(—————————————————•———————————————————————————) u u 16
Step 13 :
Equation at the end of step 13 :
v 3•(4u3+uv-3u+4v2)•(-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+————————————————————————————————————————————— u 16u
Step 14 :
v Simplify — u
Equation at the end of step 14 :
v 3•(4u3+uv-3u+4v2)•(-9u4+16u2+32uv-256v4+16v2) ((2u+(2•—))+v)+————————————————————————————————————————————— u 16u
Step 15 :
Rewriting the whole as an Equivalent Fraction :
15.1Adding a fraction to a whole
Rewrite the whole as a fraction using u as the denominator :
2u 2u • u 2u = —— = —————— 1 u
Adding fractions that have a common denominator :
15.2 Adding up the two equivalent fractions
2u • u + 2v 2u2 + 2v ——————————— = ———————— u u
Equation at the end of step 15 :
(2u2+2v) 3•(4u3+uv-3u+4v2)•(-9u4+16u2+32uv-256v4+16v2) (————————+v)+————————————————————————————————————————————— u 16u
Step 16 :
Rewriting the whole as an Equivalent Fraction :
16.1Adding a whole to a fraction
Rewrite the whole as a fraction using u as the denominator :
v v • u v = — = ————— 1 u
Step 17 :
Pulling out like terms :
17.1 Pull out like factors:
2u2 + 2v=2•(u2 + v)
Adding fractions that have a common denominator :
17.2 Adding up the two equivalent fractions
2 • (u2+v) + v • u 2u2 + uv + 2v —————————————————— = ————————————— u u
Equation at the end of step 17 :
(2u2+uv+2v) 3•(4u3+uv-3u+4v2)•(-9u4+16u2+32uv-256v4+16v2) ———————————+————————————————————————————————————————————— u 16u
Step 18 :
Trying to factor a multi variable polynomial :
18.1 Factoring2u2 + uv + 2v
Try to factor this multi-variable trinomial using trial and errorFactorization fails
Calculating the Least Common Multiple :
Prime Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
2 | 0 | 4 | 4 |
Product of all Prime Factors | 1 | 16 | 16 |
Algebraic Factor | Left Denominator | Right Denominator | L.C.M = Max {Left,Right} |
---|---|---|---|
u | 1 | 1 | 1 |
Least Common Multiple:
16u
Calculating Multipliers :
18.3 Calculate multipliers for the two fractions
Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno
Left_M=L.C.M/L_Deno=16
Right_M=L.C.M/R_Deno=1
Making Equivalent Fractions :
18.4 Rewrite the two fractions into equivalent fractions
Two fractions are called equivalent if they have the same numeric value.
For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.
To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.
L. Mult. • L. Num. (2u2+uv+2v) • 16 —————————————————— = ———————————————— L.C.M 16u R. Mult. • R. Num. 3 • (4u3+uv-3u+4v2) • (-9u4+16u2+32uv-256v4+16v2) —————————————————— = ————————————————————————————————————————————————— L.C.M 16u
Adding fractions that have a common denominator :
18.5 Adding up the two equivalent fractions
(2u2+uv+2v) • 16 + 3 • (4u3+uv-3u+4v2) • (-9u4+16u2+32uv-256v4+16v2) -108u7-27u5v+273u5-108u4v2+384u4v-3072u3v4+192u3v2+48u3v-144u3+288u2v2-288u2v+32u2-768uv5+2304uv4+432uv3-144uv2+16uv-3072v6+192v4+32v ———————————————————————————————————————————————————————————————————— = ————————————————————————————————————————————————————————————————————————————————————————————————————————————————————————————————————— 16u 16u
Final result :
-108u7-27u5v+273u5-108u4v2+384u4v-3072u3v4+192u3v2+48u3v-144u3+288u2v2-288u2v+32u2-768uv5+2304uv4+432uv3-144uv2+16uv-3072v6+192v4+32v ————————————————————————————————————————————————————————————————————————————————————————————————————————————————————————————————————— 16u